The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak is

Options

A. `0.25 muA`
B. `0.01 muA`
C. `500 muA`
D. `100 muA`

Answer

c

Explanation

Input current `=(V_(i))/(R_(i))=(0.01)/(10^(3))= 10^(-5)A`
Output collector current `=Bxx "input current"`
`= 50xx10^(-5)`
`=500A`