In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

Options

A. `10 mV`
B. `0.1 V`
C. `1.0 V`
D. `10 V`

Answer

C

Explanation

(c ) Current gain is defined as the ratio of collector current to base current, that is
`beta = (i_(C ))/(i_(B)) = (V_(0))/(V_(i))`
where `V_(0)` is output voltage and `V_(1)` is input voltage.
Given, `beta = 100, V_(i) = 10^(-2) V`
`implies V_(0) beta V_(i) = 100 xx 10^(-2) = 1 V`
Note : In common-emitter mode, the input and output signals are in opposite phase, while in the commonbase mode, the output and input signals are in same phase.