A rectangular loop carrying a current ` i` is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in the plane of the loop . If steady current ` I` is established in the wire as shown in the figure ,

Options

A. move away from the wire
B. move towards to wire
C. remain stationary
D. rotate about an axis parallel to wire

Answer

B

Explanation

(b) The force of `"attractIon"//"repulsIon"` of current carrying conductors is
`F = (mu_(0))/(2 pi) (i_(1) i_(2))/(d) l`, where `d` is distance between conductors.
`F prop (1)/(d)`
Hence, lessar the distance, more is the force. Also we know that two wires carrying current in the same direction attarct each other while that flowing in opposite direction repel each other.
In the given circuit force of attraction is more between `EF` and `AD` that of repulsion between `EF` and `BC` hence current loop is move towards the wire.