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Statement I: In Young's double-slit expe...

Statement I: In Young's double-slit experiment, the two slits are at distance d apart. Interference pattern is observed on a screen at distance D from the slits. At a point on the screen which is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to the squar of distance between two slits.
Statement II: For a dark fringe, intensity is zero

A

If both assertion and reason are ture and reason is the correct explanation of asseriton.

B

If both assertion and reason are true but reason is not the correct explanation of asseriton.

C

If assertion is true but reason is false

D

If both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
B

(b) When dark fringe is obtained at the point opposite ot one of the slits then
`S_(1) P = D`
and `S_(2) P = sqrt(D^(2) + d^(2))`
`= D(1 + (d^(2))/(D^(2)))^(1//2) = D (1 + (d^(2))/(2 D^(2)))`
Path difference `= S_(2) P - S_(1) P`
`= D (1 + (d^(2))/(2 D^(2))) - D = (d^(2))/(2D) = (lambda)/(2)`
or `lambda = (d^(2))/(D)` `implies lambda prop d^(2)`
Now, intensity of a dark fringe is zero.
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