A ray of light passes through an equilateral prism (refractive index `1.5`) such that angle of incidence is equal to angle of emergence and the latter is equal to `3//4 th` of the angle of prism. Calculate the angle of deviation.

Explanation

Here, `A = 60^@, mu = 1.5`,
`i_1 = i_2 = (3)/(4) A = (3)/(4) xx 60^@ = 45^@, delta = ?`
As `A + delta = i_1 + i_2`
:. `60^@ + delta = 45^@ + 45^@, or delta = 90^@ - 60^@ = 30^@`.