A small telescope has an objective lens of focal length `144 cm` and an eye-piece of focal length `6.0 cm`. What is the magnifying power of the telescope ? What is the separation between the objective and the eye-piece ?

Explanation

Here, `f_0 = 144 cm, f_e = 6.0 cm, m = ? , L = ?`
In normal adjustment, `m = (- f_0)/(f_e) = (-144)/(6.0) = -24`
`L = f_0 + f_e = 144 + 6.0 = 150.0 cm`.