` (tan.(pi/4 +x))/(tan*(pi/4-x))= ((1+tanx)/(1- tanx))^(2)`

Explanation

` L.H.S :' tan.(pi/4+x) = ( tan.pi/4 +tan x )/(1- tan. pi/4 * tan x) `
` :. Tan.(pi/4 +x) = (1+tanx)/(1-tanx)" "` …(1)
इसी प्रकार , `tan (pi/4-x) = (1-tanx)/(1+tanx)" "`…(2)
समीकरण ( 1 ) की समीकरण (2 ) से भाग देने पर ,
` :. (tan (pi/4+x))/(tan (pi/4-x))= ((1+tanx)/(1-tanx))/((1-tanx)/(1+tanx))`
` = ((1+tan x )/(1-tanx))xx (1+tanx)/(1-tanx)`
` = ( (1+tanx)/(1-tanx))xx(1+tanx)/(1-tanx)`
` = ((1+tanx)/(1-tanx))^(2) = R.H.S`