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h(x)=3f((x^2)/3)+f(3-x^2)AAx in (-3, 4) ...

`h(x)=3f((x^2)/3)+f(3-x^2)AAx in (-3, 4)` where `f''(x)> 0 AA x in (-3,4),` then h(x ) is

A

increasing in `((3)/(2),4)`

B

increasing in `(-(3)/(2),0)`

C

decreasing in `(-3,-(3)/(2))`

D

decreasing in `(0,(3)/(2))`

Text Solution

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The correct Answer is:
A, B, C, D
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