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How many moles of CO(2) are left if 0.15...

How many moles of `CO_(2)` are left if `0.15xx10^(21)` molecules are removed from `220 mg` of `CO_(2)`?

A

`0.00025`

B

`0.0067`

C

`0.005`

D

`0.091`

Text Solution

Verified by Experts

The correct Answer is:
A
Moles left = (Moles taken) - (Moles removed)
`= (("Mass")/("Molar Mass"))`
`- (("Number of molecules")/("Avogadro's constant"))`
`= ((220xx10^(-3) g)/(44g mol^(-1))) - ((0.15xx10^(21) "Molecules")/(6.022xx10^(23) "molecules mol"^(-1)))`
`= 0.005 "mol" CO_(2)`
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