Calculate the number of `H` atoms in `39.6g` of ammonium sulphate, `(NH_(4))_(2) SO_(4)`.

Options

A. `4.41xx10^(24) H` atoms
B. `7.86xx10^(24) H` atoms
C. `1.44xx10^(24) H` atoms
D. `5.72xx10^(24) H` atoms

Answer

C

Explanation

`underset(underset("sulphate")("ammonium"))("Mass of")rarr underset(underset("sulphate")("ammonium"))("Moles of")rarr underset(underset("sulphate")("of ammonium"))("Formula units")rarr underset(underset("atoms")("of H"))("Number")`
`36.6g(NH_(4))_(2)SO_(4)xx(1"mol"(NH_(4))_(2)SO_(4))/(132.1g(NH_(4))_(2)SO_(4))`
`xx(6.022xx10^(23)"formula units")/(1 "mol"(NH_(4))_(2)SO_(4))xx("8 H atoms")/("1 formula unit")`
`=1.44xx10^(24)` H atoms