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Red colored compound , hemoglobin presen...

Red colored compound , hemoglobin present in blood contains `0.355% Fe (AM = 56u)` If four atoms of `Fe` are present per molucule of hemoglobin, its molecular mass would be

A

`63098 u`

B

`78654 u`

C

`54786 u`

D

`98036 u`

Text Solution

Verified by Experts

The correct Answer is:
A

As there are 4 atoms of `Fe` per molecule, we have
`% Fe = (4 xx AM of Fe)/("MM of hemoglobin") xx 100%`
(`AM` is atomic mass, `MM` is molar mass)
`0.335% = (4 (56u))/(MM) xx 100%`
`:. MM = (4(56u))/(0.335%) xx 100% = 63098 u`
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