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Composition fo a colorless liquid is 84....

Composition fo a colorless liquid is `84.1% C` and `15.9% H` by mass. Its empirical formula is

A

`C_(3) H_(7)`

B

`C_(4) H_(9)`

C

`C_(5) H_(11)`

D

`CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`n_(C) = (84.1g)/(12.01g mol^(-1)) = 7.00 mol C`
`n_(H) = (15.9g)/(1.008g mol^(-1)) = 15.8 mol H`
Dividing by the smaller interger 4, we get
`n_(C) : n_(H) = (7.00)/(7.00) : (15.8)/(7.00) = 1: 2 26`
Mutiplying by the smallest interger 4, we get
`(1xx4) : (2.26xx4) = C_(4) H_(9)`
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