An electric bulb has the folloiwng specifications 100 watt, 220 volt. The resistance of bulb

Options

A. `384Omega`
B. `484Omega`
C. `344Omega`
D. `584Omega`

Explanation

To find the resistance of the electric bulb, we can use the formula relating power (P), voltage (V), and resistance (R). The formula is:

\[ P = \frac{V^2}{R} \]

Where:
- \( P \) is the power in watts (W),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).

### Step-by-Step Solution:

1. **Identify the given values**:
- Power \( P = 100 \) watts
- Voltage \( V = 220 \) volts

2. **Rearrange the formula to find resistance**:
- From the formula \( P = \frac{V^2}{R} \), we can rearrange it to solve for \( R \):
\[ R = \frac{V^2}{P} \]

3. **Substitute the known values into the formula**:
- Plugging in the values we have:
\[ R = \frac{(220)^2}{100} \]

4. **Calculate \( V^2 \)**:
- Calculate \( 220^2 \):
\[ 220^2 = 48400 \]

5. **Divide by the power**:
- Now divide by the power:
\[ R = \frac{48400}{100} = 484 \, \text{Ω} \]

6. **Conclusion**:
- The resistance of the bulb is \( 484 \, \text{Ω} \).

### Final Answer:
The resistance of the electric bulb is **484 ohms**.

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