Four cell each of emf 2 V and internal resistance 1 ohm are connected n parallel with an external resistance of 6 ohm. The current in the external resistance is

Options

A. 0.32 A
B. 0.16 A
C. 0.2 A
D. 0.6 A

Explanation

To solve the problem, we need to find the current flowing through the external resistance when four cells, each with an emf of 2 V and an internal resistance of 1 ohm, are connected in parallel with an external resistance of 6 ohms.

### Step-by-Step Solution:

1. **Identify the Parameters:**
- Number of cells (n) = 4
- Emf of each cell (E) = 2 V
- Internal resistance of each cell (r) = 1 ohm
- External resistance (R) = 6 ohm

2. **Calculate the Total Emf:**
- Since the cells are connected in parallel, the total emf remains the same as that of one cell:
\[ E_{total} = E = 2 \, \text{V} \]

3. **Calculate the Total Internal Resistance:**
- The internal resistances of the cells in parallel can be calculated using the formula:
\[ r_{total} = \frac{r}{n} = \frac{1 \, \text{ohm}}{4} = 0.25 \, \text{ohm} \]

4. **Calculate the Total Resistance in the Circuit:**
- The total resistance in the circuit (R_total) is the sum of the external resistance and the equivalent internal resistance:
\[ R_{total} = R + r_{total} = 6 \, \text{ohm} + 0.25 \, \text{ohm} = 6.25 \, \text{ohm} \]

5. **Calculate the Current through the External Resistance:**
- Using Ohm's Law, the current (I) can be calculated as:
\[ I = \frac{E_{total}}{R_{total}} = \frac{2 \, \text{V}}{6.25 \, \text{ohm}} = 0.32 \, \text{A} \]

6. **Conclusion:**
- The current flowing through the external resistance is:
\[ I = 0.32 \, \text{A} \]

### Final Answer:
The current in the external resistance is **0.32 A**.

---