A student is asked to connected four cells of emf of 1 V and internal resistance 0.5 ohm in series with an external resistance of 1 ohm. But one cells is wrongly connected by him with its terminal reversed, the current in the ciruit is

Options

A. `(1)/(3)A`
B. `(2)/(3)A`
C. `(3)/(4)A`
D. `(4)/(3)A`

Answer

B

Explanation

`i=((N-2n)E)/(R+Nr)=((4-2)xx1)/(1+4xx0.5)=(2xx1)/(3)`