Home
Class 12
PHYSICS
In an experiment to determine the intern...

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

A

`2.2Omega`

B

`1.1Omega`

C

`3.3Omega`

D

`0.5Omega`

Text Solution

Verified by Experts

The correct Answer is:
D

`r=R[(l_(1)-l_(2))/(l_(2))]`
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 2 C.W|59 Videos
  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 2 H.W|45 Videos
  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 1 C.W|64 Videos
  • COMMUNICATION SYSTEM

    NARAYNA|Exercise Level-II(H.W)|25 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos

Similar Questions

Explore conceptually related problems

The internal resistance of a cell by potentiometer is given by

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

The emf of cell is balanced by balancing length 450 cm . When the resistance of 10 Omega is connected across the cell, balancing length changes by 100 cm. The internal resistance of a cell is

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

Determination Of Internal Resistance Of A Cell

A 2.0 V potentiometer is used to determine the internal resistance of 1.5 V cell. The balance point of the cell in the circuit is 75 cm . When a resistor of 10Omega is connected across cel, the balance point sifts to 60 cm . The internal resistance of the cell is

A cell when balanced with potentiometer gave a balance length of50 cm. 4.5 Omega external resistance is introduced in the circuit, now it is balanced on 45 cm. The internal resistance of cell is

A 2.0V potentiometer is used to determine the internal resistance ofa I.SY cell. The balance point of the cell in the open circuit is obtained at 75cm. When· a resistor of 10Omega is connected across the cell, the balance point shifts to 60cm. The internal resistance of the cell is:

NARAYNA-CURRENT ELECTRICITY-Level 1 H.W
  1. The emf of a cell is 2 V. When the terminals of the cell is connected ...

    Text Solution

    |

  2. If the external resistance is equal to internal resistance of a cell o...

    Text Solution

    |

  3. Two cells each of emf 10 V and each 1Omega internal resistance are use...

    Text Solution

    |

  4. The figure below shows current in a part of electric circuit. The curr...

    Text Solution

    |

  5. Current in the ain circuit shows is

    Text Solution

    |

  6. Find i for the given loop.

    Text Solution

    |

  7. The potential difference between points A nd B is

    Text Solution

    |

  8. In wheat stone bridge P and Q are approximately equal. When Ris 500Ome...

    Text Solution

    |

  9. To balance the bridge in the circuit in the circuit the values of R is

    Text Solution

    |

  10. The points in a metre bridge is at 35.6 cm. if the resistances in the ...

    Text Solution

    |

  11. In a metre bridge expt, when the resistances in the gaps are interchan...

    Text Solution

    |

  12. When an unknown resistance and a resistance 6Omega are connected in th...

    Text Solution

    |

  13. When unknown resistance and a resistance of 5 Omega are used in left a...

    Text Solution

    |

  14. In a meter bridge experiment, null point is obtained at 20 cm from one...

    Text Solution

    |

  15. In a potentiometer the balance length with standard cadmium cell is 50...

    Text Solution

    |

  16. Two cells of emf's E(1) and E(2) when placed in series produce null de...

    Text Solution

    |

  17. Then 6 identical calls of no internal resistance are connected in seri...

    Text Solution

    |

  18. In an experiment to determine the internal resistance of a cell with p...

    Text Solution

    |

  19. The resistivity of a potentiometer wire is 40xx10^(-8)Omega-m and its ...

    Text Solution

    |

  20. The emf of a cell is Ev, and its its internal resistance is 1Omega. A ...

    Text Solution

    |