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The emf of a cell is Ev, and its its int...

The emf of a cell is `Ev`, and its its internal resistance is `1Omega`. A resistance of `4Omega` is joined to battery in parallel. This is connected in secondary circuit of potentiometer. The balancing length is 160 cm. If 1 V cell balances for 100 cm of potentiometer wire, the emf of cell E is

A

1 V

B

3 V

C

2 V

D

4 V

Text Solution

Verified by Experts

The correct Answer is:
C
`r=R[(l_(1)-l_(2))/(l_(2))]`
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