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A particale moves under the effect of a ...

A particale moves under the effect of a force `F = Cs` from `x = 0` to `x = x_(1)`. The work down in the process is

A

`C^(2)//x_(1)^(2)`

B

`Cx_(1)^(2)`

C

`.^(1)//_(2) Cx_(1)^(2)`

D

`.^(1)//_(2)C^(2)//x_(1^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`W = underset(0) overset(x_(1))int Fdx`.
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