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The speed of a car changes from 0 to 5 m...

The speed of a car changes from `0` to `5 ms^(-1)` in the first phase and from `5 ms^(-1)` to `10 ms^(-1)` in the second phase and from `10 ms^(-1)` to `15 ms^(-1)` during the third phase. In which phase the increase in kinetic energy is more ?

A

first phase

B

second phase

C

third phase

D

same in all the three phases

Text Solution

Verified by Experts

The correct Answer is:
C

`Delta KE = (1)/(2) m(v^(2) -u^(2))`.
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