A mass of `2.9 kg` is suspended from a string of length `50 cm` and is at rest . Another body of mass `100 gm` which is moving horizontal with a velocity of `150 m//s` strikes it . After striking the two bodies combine together . Tension in the string , when it is at an angle of `60^(@)` with the velocity is : `g = 10 m//s^(2)`

Options

A. 140 N
B. 135 N
C. 125 N
D. 90 N

Answer

B

Explanation

`v_(common) = (m u)/(M+m)` and `T = mg cos theta + (mv^(2))/(r)`
Where `V = sqrt(v_("bottom")^(2) -2gr(1-cos theta))`.