A ball is let to fall frm a height `h_(0)`. It makes 'n' collisions with the horizontal ground. If after 'n' collisions it rebounds with a velocity `v_(n)` and the ball rises to a height `h_(n)`, then the coefficient of restitution for the collision is

Options

A. `e = ((h_(n))/(h_(o)))^((1)/(2n))`
B. `e = ((h_(n))/(h_(o)))^((n)/(2))`
C. `e = ((h_(0))/(h_(n)))^((n)/(2))`
D. `e = ((h_(0))/(h_(n)))^((1)/(2n))`

Answer

A

Explanation

`h_(n) = e^(2n) h_(0)`.