A ball is falling freely from a certain height. When it reached `10 m` height from the ground its velocity is `v_(0)`. It collides with the horizontal ground and loses `50 %` of its energy and rises back to height of `10 m`. The value of velocity `v_(0)` is

Options

A. `7 ms^(-1)`
B. `10 ms^(-1)`
C. `14 ms^(-1)`
D. `16 ms^(-1)`

Answer

C

Explanation

`(1)/(2)((1)/(2) m v_(0)^(2) + m g h_(1)) = m g h_(2)`.