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int(sin2x)/(sin5x.sin3x)dx=...

`int(sin2x)/(sin5x.sin3x)dx=`

A

`logabs(sin3x)-logabs(sin5x)+c`

B

`1/3logabs(sin3x)+1/5logabs(sin5x)+c`

C

`1/3logabs(sin3x)-1/5logabs(sin5x)+c`

D

`(logabs(sin2x))/(logabs(sin3x)+logabs(sin5x))+c`

Text Solution

Verified by Experts

The correct Answer is:
C
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