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The integral intcos(log(e)x)dx is equal ...

The integral `intcos(log_(e)x)dx` is equal to: (where C is a constant of integration)

A

`1/2x[cos(log_(e)x)+sin(log_(e)x)]+c`

B

`x[cos(log_(e)x)+sin(log_(e)x)]+c`

C

`1/2x[cos(log_(e)x)-sin(log_(e)x)]+c`

D

`x[cos(log_(e)x)-sin(log_(e)x)]+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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