In this reaction
`C_(6)H_(5)NH_(2)+HCl+NaNO_(2)rarrX`. Product X is

Options

A. Aniline hydrochloride
B. Nitro aniline
C. Benzenediazonium chloride
D. None of these

Explanation

To solve the reaction \( C_6H_5NH_2 + HCl + NaNO_2 \rightarrow X \), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Aniline (\( C_6H_5NH_2 \))
- Hydrochloric acid (\( HCl \))
- Sodium nitrite (\( NaNO_2 \))

### Step 2: Understand the Reaction Conditions
Aniline reacts with hydrochloric acid to form aniline hydrochloride. The presence of sodium nitrite in acidic conditions is crucial for the formation of a diazonium salt.

### Step 3: Formation of Diazonium Salt
When aniline hydrochloride is treated with sodium nitrite (\( NaNO_2 \)) in the presence of hydrochloric acid, it leads to the formation of benzene diazonium chloride. The reaction can be summarized as follows:

\[ C_6H_5NH_2 + HCl + NaNO_2 \rightarrow C_6H_5N_2Cl + NaCl + H_2O \]

### Step 4: Identify the Product
The product \( X \) formed in this reaction is benzene diazonium chloride, represented as \( C_6H_5N_2Cl \).

### Final Answer
Thus, the product \( X \) is benzene diazonium chloride (\( C_6H_5N_2Cl \)).

---