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If |x-1|+|x-2|+|x-3|=k, x epsilon R then...

If `|x-1|+|x-2|+|x-3|=k, x epsilon R` then value of `k` for which given equation has exactly one solution.

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Verified by Experts

The correct Answer is:
2
If `|x-1|+|x-2|`………….
When `k = 2`

`y = 2` line cut the graph of
`y = |x-1|+|x-2|+|x-3|` at one point.
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