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A point A(2, 1) is outside the circle x^...

A point A(2, 1) is outside the circle `x^2+y^2+2gx+2fy+c=0` & AP, AQ are tangents to the circle.The equation of the circle circumscribing the triangle APQ is: a. (x+g)(x-2)+(y+f)(y-1)=0 b. (x+g)(x-2)-(y+f)(y-1)=0 c. (x-g)(x+2)+(y-f)(y+1)=0 d. (x-g)(x-2)+(y-f)(y-1)=0

A

`(x+g)(x-2)+(y+f)(y-1)=0`

B

`(x+g)(x-2)-(y+f)(y-1)=0`

C

`(x-g)(x+2)+(y-f)(y+1)=0`

D

`(x+g)(x+2)+(y+f)(y+1)=0`

Text Solution

Verified by Experts

The correct Answer is:
A
A point `A(2, 1)` is ……….

`AO` will be diameter of circle `(x-2)(x+g)+(y-1)(y+f)=0`
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