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If the equation x^2-3kx+2e^(2logk)-1=0 h...

If the equation `x^2-3kx+2e^(2logk)-1=0` has real roots such that the product of roots is `7` then the value of `k` is

Text Solution

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The correct Answer is:
`4`
`alphabeta = 2e^(2log_(e)k) - 1 = 7`
`rArr k^(2) = 4 rArr k = -+2`
`x^(2) - 3kx + = 0`
`D = 9k^(2) - 28 gt 0` for `k = 2`
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