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Polynomial P(x) contains only terms of a...

Polynomial `P(x)` contains only terms of aodd degree. when `P(x)` is divided by `(x - 3)`, the ramainder is `6`. If `P(x)` is divided by `(x^(2) - 9)` then remainder is `g(x)`. Then find the value of `g(2)`.

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To solve the problem, we need to find the value of \( g(2) \) where \( g(x) \) is the remainder when the polynomial \( P(x) \) is divided by \( x^2 - 9 \). ### Step-by-Step Solution: 1. **Understand the Polynomial**: Since \( P(x) \) contains only terms of odd degree, it can be expressed in the general form of odd degree polynomials, such as \( P(x) = a_n x^n + a_{n-2} x^{n-2} + \ldots + a_1 x \). 2. **Remainder Theorem**: According to the Remainder Theorem, when \( P(x) \) is divided by \( (x - 3) \), the remainder is \( P(3) \). We know that \( P(3) = 6 \). 3. **Dividing by \( x^2 - 9 \)**: The polynomial \( x^2 - 9 \) can be factored as \( (x - 3)(x + 3) \). When dividing \( P(x) \) by \( x^2 - 9 \), the remainder \( g(x) \) must be a polynomial of degree less than 2. Therefore, we can express \( g(x) \) in the form: \[ g(x) = ax + b \] 4. **Finding \( g(3) \)**: Since \( P(x) = (x^2 - 9)Q(x) + g(x) \), substituting \( x = 3 \): \[ P(3) = g(3) \] We already know \( P(3) = 6 \), so: \[ g(3) = 6 \] 5. **Finding \( g(-3) \)**: Similarly, substituting \( x = -3 \): \[ P(-3) = g(-3) \] Since \( P(x) \) is an odd function (only contains odd degree terms), we have: \[ P(-3) = -P(3) = -6 \] Thus: \[ g(-3) = -6 \] 6. **Setting Up the System of Equations**: Now we have two equations: - From \( g(3) = 6 \): \[ 3a + b = 6 \quad \text{(1)} \] - From \( g(-3) = -6 \): \[ -3a + b = -6 \quad \text{(2)} \] 7. **Solving the System of Equations**: Subtract equation (2) from equation (1): \[ (3a + b) - (-3a + b) = 6 - (-6) \] This simplifies to: \[ 6a = 12 \implies a = 2 \] Now substitute \( a = 2 \) back into equation (1): \[ 3(2) + b = 6 \implies 6 + b = 6 \implies b = 0 \] 8. **Finding \( g(x) \)**: Thus, we have: \[ g(x) = 2x + 0 = 2x \] 9. **Calculating \( g(2) \)**: Finally, we need to find \( g(2) \): \[ g(2) = 2(2) = 4 \] ### Final Answer: \[ g(2) = 4 \]

To solve the problem, we need to find the value of \( g(2) \) where \( g(x) \) is the remainder when the polynomial \( P(x) \) is divided by \( x^2 - 9 \). ### Step-by-Step Solution: 1. **Understand the Polynomial**: Since \( P(x) \) contains only terms of odd degree, it can be expressed in the general form of odd degree polynomials, such as \( P(x) = a_n x^n + a_{n-2} x^{n-2} + \ldots + a_1 x \). 2. **Remainder Theorem**: ...
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