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The remainder when (1!)^(2) + (2!)^(2) +...

The remainder when `(1!)^(2) + (2!)^(2) + (3!)^(2) + ….. + (100!)^(2)` is divided by `144` is `ab` then `(a)/(b) =`

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The correct Answer is:
4
`:' (4!)^(2), (5!)^(2), ………,(100!)^(2)` are divisible by `144`
`:.` Remainder `= 4! = ab , (a)/(b) = (a)/(1) = 4`
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