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If x, y in [0,2pi] then find the total n...

If `x, y in [0,2pi]` then find the total number of order pair `(x,y)` satisfying the equation `sinx .cos y = 1`

A

`3`

B

`6`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
A
`sin x cos y = 1`
`sin x = 1` and `cos y = 1` or `sin x = -1` & `cos y = -1`
`x = (pi)/(2), x = (3pi)/(2)`
`y = 0, 2pi , y = pi`
`((pi)/(2),0),((pi)/(2),2pi)((3pi)/(2),pi)`
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