A particle is projected from a point P (2,0,0)m with a velocity `10(m)/(s)` making an angle `45^@` with the horizontal. The plane of projectile motion passes through a horizontal line PQ which makes an angle of `37^@` with positive x-axis, xy plane is horizontal. The coordinates of the point where the particle will strike the line PQ is

Options

A. `(10,6,0) m`
B. `(8,6,0)m`
C. `(10,8,0) m`
D. `(6,10,0)m`

Answer

A

Explanation

Range `= 10 m`
For point where particle strikes line `PQ`
`:. X` coordinate `= 10 cos 37^(@) + 2 = 10 m`
`y` coordinate `= 10 sin 37^(@) = 6m`
`z` coordinate `= 0m`.