A hollow cubical box P is moving on a smooth horizontal surface in the x-y plane with constant acceleration of `vec(a) = 3 hat (i) + 4 hat (j) m//s^(2)`.A block Q of mass 2 kg is at rest inside the cubical box as shown in figure. If the coefficient of friction between the surface of the cube P and the block Q is 0.6. Then the force of friction between P and Q is :

Options

A. 5 N
B. 8 N
C. 12 N
D. 10 N

Answer

D

Explanation

`a = sqrt(3^(2)+4^(2))=5m//s`
Friction force `f = ma = 2 xx 5 = 10 N`