A satellite with mass 2000 kg and angular momentum magnitude `2 xx 10^(12) kg.m^(2)//s` is moving in an elliptical orbit around a plate. The rate at which area is swept out by the satellite around the planet, is equal to

Options

A. `1 xx 10^(9) m^(2)//s`
B. `5 xx 10^(9) m^(2)//s`
C. `5 xx 10^(8) m^(2)//s`
D. `4 xx10^(15) m^(2)//s`

Answer

C

Explanation

`(dA)/(dt)=(L)/(2m)=(2xx10^(12))/(2 xx 2000)=5xx 10^(8) m^(2)//s`