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In the arrangement shown, W(1) = 200N, W...

In the arrangement shown, `W_(1) = 200N, W_(2) = 100 N,mu = 0.25` for all surfaces in contact. The block `W_(1)` just slides under the block `W_(2)`

A

A pull of 50 N is to be applied on `W_(1)`

B

A pull of 90 N is to be applied on `W_(1)`

C

Tension in the string AB is 10 N

D

Tension in the string AB is 20 N

Text Solution

Verified by Experts

The correct Answer is:
B, D

For `W_(2) `:
`N_(2)=T sin 45^(@) =W_(2)=100`....(A)
`T cos45^(@) = 0.25 N_(2)`...(B)
`rArr T= 20sqrt(2)N,N_(2)=80N`

For `W_(1) :`
`P = 0.25 (N_(1)+N_(2))` ....(C)
`N_(2) +W_(1)=N_(1)`....(D)
`rArr N_(1) = 280 N`
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