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If `f(x)` is a differentiable function wherever it is continuous and `f'(c_1)=f'(c_2)=0` `f''(c_1).f''(c_2)<0, f(c_1)=5,f(c_2)=0` and `(c_1ltc_2)` . If `f(x) ` is continuous in `[c_1,c_2]` and `f''(c_1)-f''(c_2)>0` then minimum number of roots of `f'(x)=0` in `[c_1-1,c_2+1]` is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B, C

Here `c_(1)` is local maximum and `c_(2)` is local minimum `impliesf^(')(x)=0` has atleast two roots in `[c_(1)-1,c_(2)+1]`
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