A five digits number divisible by 3 is to be formed using the number 0,1,2,3,4 and 5 without repetition. The number of such numbers are `m^(3)` then m is equal to

Answer

6

Explanation

since a five digits no. if formed using the digits {0,1,2,3,4 and 5} divisible by 3 i.e., only possible
Case-1 using digits 0,1,2,4,5 no. of ways `=4.4.3.2.1=96`
Case-2 using digits 1,2,3,4,5 no of ways `5,4,3,2,1=120`
Total numbers formed `=120+96=216=6^(3)`
`=120+96=216=6^(3)`