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From a point P outside a circle with centre at C, tangents PA and PB are drawn such that `(1)/((CA)^(2))+(1)/((PA)^(2))=(1)/(16)`, then fid the length of chord AB.

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Verified by Experts

The correct Answer is:
8

`tantheta=(r)/(PA)`
Given `(1)/(r^(2))+(1)/(PA^(2))=(1)/(16)`
`implies(cot^(2)theta+1)/((PA)^(2))=(1)/(16)`
`Pasintheta=4=ximplies2x=8`
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