Home
Class 12
CHEMISTRY
Two solutions of a substances (non elect...

Two solutions of a substances (non electrolyte) are mixed in the following manner. 480 ml of `1.5M` first solution `+520 mL` of `1.2M` second solution. What is the molarity of the final mixture?

A

`1.20M`

B

`1.50M`

C

`1.344M`

D

`2.70M`

Text Solution

Verified by Experts

The correct Answer is:
C

Total milimoles of solute `=480xx1.5+520xx1.2=720+624=1344`.
Total volume `=480+520=1000`.
Molarity of the final mixture `=(1344)/(1000)=1.344M`.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE|Exercise EXERCISE-3(PART-3)|30 Videos
  • SOLUTIONS

    RESONANCE|Exercise Advabced Level Problems (PART-1)|71 Videos
  • SOLUTIONS

    RESONANCE|Exercise EXERCISE-3(PART-1)|14 Videos
  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos
  • STEREOISOMERISM

    RESONANCE|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|22 Videos

Similar Questions

Explore conceptually related problems

Two solutions of a substance (non-electrolyte) are mixed in the following manner. 480 mL of 1.5M first solution +520 mL of 1.2M second solution. What is the molarity of the final mixture?

Two solutions of a substance (non-electrolyte) are mixed in the following manner , 480 mL of 1.5 M [first solution ] + 520 mL of 1.2 M [second solution ] . What is the molarity of the final mixture ?

Two solutions of a substance (non-electroyte) are mixed in the following manner 480 mL of 1.5M of first solution with 520 mL or 1.2M of second solution. The molarity of final solution is:

200 ml of water is added of 500 ml of 0.2 M solution. What is the molarity of this diluted solution?