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Density of 2.05 M solution of acetic aci...

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

A

`3.28` mol `kg^(-1)`

B

`2.28` mol `kg^(-1)~

C

`0.44` mol `kg^(-1)`

D

`1.14` mol `kg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Molality, `m=(M)/(1000d-MM_(2))xx1000`
where `M=` molarity, `d=` density, `M_(2)=` molecular mass
`m=(2.05)/(1000xx1.02-2.05xx60)=2.28 "mol" kg^(-1)`
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