Home
Class 12
CHEMISTRY
A 5.25% solution of a substance is isoto...

A `5.25%` solution of a substance is isotonic with a `1.5%` solution of urea (molar mass `= 60g mol^(-1)`) in the same solvent. If the densities of both the solutions are assumed to be equal to `1.0 g cm^(-3)`, molar mass of the substance will be:

A

`105.0g "mol"^(-1)`

B

`210.0g "mol"^(-1)`

C

`90.0g "mol"^(-1)`

D

`15.0g "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

Isotonic solution have same osmotic pressure.
`pi_(1)=C_(1)RT,pi_(2)=C_(2)RT`
For isotonic solution, `pi_(1)=pi_(2)`
`therefore C_(1)=C_(2)`.
or `(1.5//60)/(V)=(5.25//M)/(V)` [where `M=` molecular weight of the substance]
or `(1.5)/(60)=(5.25)/(M)=210`.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE|Exercise EXERCISE-3(PART-3)|30 Videos
  • SOLUTIONS

    RESONANCE|Exercise Advabced Level Problems (PART-1)|71 Videos
  • SOLUTIONS

    RESONANCE|Exercise EXERCISE-3(PART-1)|14 Videos
  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos
  • STEREOISOMERISM

    RESONANCE|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|22 Videos

Similar Questions

Explore conceptually related problems

A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass= 60gmol^(-1) )in the same solvent.If the densities of both the solutions are assumed to be equal to 1.0gcm^(-3) ,molar mass of the substance will be:

A 1% aqueous solution (M/V) of a certain substance is isotonic with a 3% solution of glucose (M. mass 180). The molar mass of the substance is