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A solution prepared by dissolving 1.25g ...

A solution prepared by dissolving `1.25g` of oil of winter green (methyl sallicylate) in `99.0g` of benzene has a boiling point of `80.31^(@)C`. Determine the molar mass of this compound. (`B.P.` of pure benzene `=80.10^(@)C` and `K_(b)` for benzene `=2.53^(@)C kg "mol".1`)

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To determine the molar mass of oil of wintergreen (methyl salicylate) using the boiling point elevation method, we can follow these steps: ### Step 1: Identify the given data - Mass of solute (methyl salicylate), \( W_b = 1.25 \, \text{g} \) - Mass of solvent (benzene), \( W_a = 99.0 \, \text{g} \) - Boiling point of the solution, \( T_{\text{solution}} = 80.31^\circ \text{C} \) - Boiling point of pure benzene, \( T_{\text{benzene}} = 80.10^\circ \text{C} \) - Boiling point elevation constant for benzene, \( K_b = 2.53 \, \text{°C kg/mol} \) ### Step 2: Calculate the elevation in boiling point, \( \Delta T_b \) \[ \Delta T_b = T_{\text{solution}} - T_{\text{benzene}} = 80.31^\circ \text{C} - 80.10^\circ \text{C} = 0.21^\circ \text{C} \] ### Step 3: Use the boiling point elevation formula The formula for boiling point elevation is given by: \[ \Delta T_b = K_b \cdot \frac{W_b}{W_a} \cdot \frac{1000}{M_b} \] Where: - \( \Delta T_b \) is the elevation in boiling point - \( K_b \) is the ebullioscopic constant - \( W_b \) is the mass of the solute - \( W_a \) is the mass of the solvent - \( M_b \) is the molar mass of the solute ### Step 4: Rearrange the formula to solve for \( M_b \) Rearranging the formula gives: \[ M_b = K_b \cdot \frac{W_b \cdot 1000}{W_a \cdot \Delta T_b} \] ### Step 5: Substitute the values into the equation Substituting the known values: \[ M_b = 2.53 \, \text{°C kg/mol} \cdot \frac{1.25 \, \text{g} \cdot 1000}{99.0 \, \text{g} \cdot 0.21 \, \text{°C}} \] ### Step 6: Perform the calculations 1. Calculate the numerator: \[ 2.53 \cdot 1.25 \cdot 1000 = 3162.5 \] 2. Calculate the denominator: \[ 99.0 \cdot 0.21 = 20.79 \] 3. Now, divide the results: \[ M_b = \frac{3162.5}{20.79} \approx 152.116 \, \text{g/mol} \] ### Final Result The molar mass of oil of wintergreen (methyl salicylate) is approximately \( 152.116 \, \text{g/mol} \). ---
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