A solution containing 3.24 g of a nonvolatile nonelectrolyte and 200 g of water boils at 100. `130^(@)"C"` at 1atm. What is the molecular weight of the solute?`("K"_("b") "for water 0.513"^(@)"C"//"m")`

Answer

`"64.0 g/mol"`

Explanation

Solute-B, Water-A
`Delta"T"_("b")=100.130-100`
`=0.130`
`Delta"T"_("b")="K"_("b")xx("w"_("B")xx1000)/("m"_("B")xx"w"_("A")"(gm)")`
`0.130=0.513xx(3.24xx1000)/("m"_("B")xx200)`
`"m"_("B")=64"gm mol"^(-1)`