The pressure amplitude in a sound wave from a radio receive is `2.0 xx 10^(-3)N//m^(2)` and the intensity at a point is `10^(-6)W//m^(2)`. If by turning the "Volume" knob the pressure amplitude is increased to `3 xx 10^(-2)N//m^(2)`, evalute the intensity.

Explanation

The intensity is proportional to the square of the pressure amplitude.
Thus, `(I')/(I) = ((p_(0)^('))/(p_(0)))`
`I' = ((p_(0)^('))/(p_(0))) I = ((3)/(2.0))^(2) xx 10^(-6)W//m^(2) = 2.25 xx 10^(-6)W//m^(2)`.