The distance between two consecutive nodes in a stationary waves is `15 cm`. If the speed of the wave the `300 m//s`, calculate the frequency.

Answer

`(lambda)/(2) = 15cm` or `lambda = 30 cm = 0.3 m`,
`v = (c)/(lambda) = (3 xx 10^(8))/(0.3) = 10^(9) Hz`