Evaluate indefinite integration.
(i) `x=intdt " "` (ii) `int t dt " "` (iii) `x=int (2t) dt" "` (iv) `x=int (t^(2)) dt " "`
(v) `x=int (-(2)/(t^3))dt`

Explanation

(i) `x=t+c " "` (ii) `x=(t^(2))/(2)+c" "` (iii) `x=(2t^(2))/(2)+c=t^(2)+c`
(iv) `x=t^(3)/(3)+c" "` (v) `x=-2intt^(-3)dtrArrx=-2((t^(-2))/(-2))+c=t^(-2)+c`