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Work function of a metal is 2.3eV and on...

Work function of a metal is 2.3eV and on `1.0 cm^(2)` area of that metal, a light of intensity `8.6 xx 10^(3) W.m^(-2)` is incident. That intensity is distributed equally among the wavelength `4144 Å, 4972 Å and 6216 Å`. If no ray is lost due to scattering and if each of the photons of proper energy can emit photoelectrons, what will be the number of photoelectrons emitted in 2 s? `(h = 6.63 xx 10^(-34) J.s, 1eV = 1.6 xx 10^(-19)J)`

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