Home
Class 12
PHYSICS
Ultraviolet rays of wavelengths 800 Å an...

Ultraviolet rays of wavelengths `800 Å` and `700 Å` fall on a hydrogen atom initially in its minimum energy state. As a result, electrons having energies 1.8 eV and 4.0 eV are emitted. Determine the value of Planck's constant

Text Solution

Verified by Experts

`6.57 xx 10^(-34) J.s`
Promotional Banner

Topper's Solved these Questions

  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Exercise (Hots Numerical Problems)|4 Videos

  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Entrance Corner (Assertion- Reason Type)|10 Videos

  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise Exercise (Problem Set- I)|41 Videos

  • OPTICAL INSTRUMENTS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|8 Videos

  • QUESTION PAPER OF NEET 2017

    CHHAYA PUBLICATION|Exercise QUESTION PAPERS OF (NEET) (2017)|39 Videos

Similar Questions

Explore conceptually related problems

The ionisation potential hydrogen atom is 13.6 V. when the atom is in n-th energy state. The maximum energy of the emitted photon is 12.1eV . What is the value of n?

On absorption of radiation of wavelength 1219 Å, a hydrogen atom is excited from ground state to the n-th energy state. What is the value of n?

When ultraviolet rays of wavelength 620 Å is incident on a hydrogen atom in the ground state, its electron is emitted with a velocity of 1.5 xx10^(6) m *s^(-1) . What is the ionisation energy of hydrogen ? Given , h= 6.625xx10^(-34)J *s , mass of electron = 9.1 xx 10^(-31)kg, c=3xx 10^(8)m*s^(-1) and 1 eV=1.6xx 10^(-19)J .

In absorbing 10.2 eV energy, the electron of a hydrogen atom jumps from its initial orbit to next higher energy orbit . As the electron returning to the former orbit, a photon is emitted. What is the wavelength of this photon ?

An electron in a hydrogen -like atom is in an excited state. It has a total energy of -3.4 eV. Calculate the kinetic energy of the electron.

Photoelectric threshold wavelength for a metal is 3800 Å . Find the maximum kinetic energy of emitted photoelectron, when ultraviolet radiation of wave length 2000Å is incident on the metal surface. Planck's constant, h = 6.62 xx 10^(-34) J.s

If the electron in a hydrogen atom jumps from the second excited state to its ground state, the wavelength of the emitted radiation becomes 1026 Å . Determine the value of Rydberg constant from this data.

An electron in a hydrogen atom in its ground in its ground state absorbs 1.5 times as much energy as the minimum required for it escape from the atom what is the velocity of the emitted electron?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Energy of which quantum state of He^+ ion will be equal to the ground level energy of hydrogen ?