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A metal plate is exposed to light with w...

A metal plate is exposed to light with wavelength `lambda`. It is observed that electrons are ejected from the surface of the metal plate. When a retarding uniform electric field E is imposed, no electron can move away from the plate farther than a certain distance d. Then the threshold wavelength `lambda_(0)` for the material of plate is ( e is the electronic charge, h is Planck's constant and c is the speed of light)

A

`lambda_(0) = ((1/lambda)-(hc)/(eEd))^(-)`

B

`lambda_(0) = (1/lambda-(eEd)/(hc))^(-1)`

C

`lambda_(0)= lambda-(hc)/(eEd)`

D

`lambda_(0)= lambda-(eEd)/(hc)`

Text Solution

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