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A proton with KE equal to that a photono...

A proton with KE equal to that a photono (E = 100 keV). `lambda_(1)` is the wavelength of proton and `lambda_(2)` is the wavelength of photon. Then `lambda_(1)/lambda)_(2)` is proportional to:

A

`E^(1/2)`

B

`E^(-1/2)`

C

E

D

`E^(-1)`

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